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What is the mass balance equation for 1.0uM of an acidic indicator dye, HIn, with pKa=6.0,...

What is the mass balance equation for 1.0uM of an acidic indicator dye, HIn, with pKa=6.0, in aqueous solution buffered at pH 8.5. (some assumptions may be made.)

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Answer #1

The indicator at equillibrium will have the following species:

HIn + H2O ===> In- + H3O+

Depending upon the pH of the solution, the equillibrium will be shifted either to the right or left. For example, if the pH<7 the equillibrium is shifted to the left as the H3O+ is more. On the other hand, if the pH>7 the equillibrium is shifted to the right.

Thus the mass balance equation will be,

Assumptions: In- > HIn

CHIn, In- = [HIn] + [In-] = 1.0 uM + 1.0 uM = 2.0 uM

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