Electrons are ejected from sodium metal by any light that has a wavelength shorter than 544 nm. What is the kinetic energy of an electron (in J) that is ejected from sodium by light with a wavelength of 385 nm?
cutoff wavelength is 544 nm
we have below equation to be used:
Energy = Planck constant*speed of light/wavelength
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(5.44*10^-7 m)
= 3.654*10^-19 J
This is cut off energy. Eo = 3.654*10^-19 J
Now find the energy of photons which ejects an electron
we have below equation to be used:
Energy = Planck constant*speed of light/wavelength
=(6.626*10^-34 J.s)*(3.0*10^8 m/s)/(3.85*10^-7 m)
= 5.163*10^-19 J
E = 5.163*10^-19 J
Kinetic energy,
KE = E - Eo
= 5.163*10^-19 J - 3.654*10^-19 J
= 1.51*10^-19 J
Answer : 1.51*10^-19 J
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