Question

**A ground-state H atom absorbs a photon of wavelength
92.62 nm. What higher energy level did the electron
reach?**

Answer #1

4 a) A hydrogen atom in the ground state absorbs a photon of
wavelength 97.2 nm. What energy level does the electron reach?
b) This excited atom then emits a photon of wavelength 1875.4
nm. What energy level does the electron fall to?

A hydrogen atom in the ground state absorbs a photon of
wavelength 95.0 nm.
What energy level does the electron reach?
This excited atom then emits a photon of wavelength 434.1 nm.
What energy level does the electron fall to?
-I know this question has already been asked on Chegg but each
question I go to has different calculations and I can't get the
right answer.

a ground state hydrogen atom absorbs a photon of light having a
wavelength of 93.73 nm. it then gives off a photon having a
wavelength of 410.1 nm. what is the final state of the hydrogen
atom?

A ground state hydrogen atom absorbs a photon of light having a
wavelength of 93.73 nm. It then gives off a photon having a
wavelength of 2624 nm. What is the final state of the hydrogen
atom?

A ground state hydrogen atom absorbs a photon of light having a
wavelength of 92.57 nm. It then gives off a photon having a
wavelength of 954.3 nm. What is the final state of the hydrogen
atom? Values for physical constants can be found here.

A
ground state hydrogen atom absorbs a photon light having a
wavelength of 92.57 nm. It then gives off a photon having a
wavelength of 1944 nm. What is the final state of the hydrogen
atom?
I got Nf=1.14 and it wasn't right

A ground state hydrogen atom absorbs a photon of light having a
wavelength of 92.27 nm. It then gives off a photon having a
wavelength of 383.4 nm. What is the final state of the hydrogen
atom? Values for physical constants can be found here. nf=
please try to show solution

Originally, a H-atom is in an n=2 state.
a) After this atom absorbs a 77-nm photon, the electron is
ejected. The energy of the absorbed photon is....
b) The kinetic energy of the ejected electron is...

A mercury atom is initially in its lowest possible (or ground
state) energy level. The atom absorbs a photon with a wavelength of
185 nm and then emits a photon with a frequency of 4.924 x 10^14
Hz. At the end of this series of transitions, the atom will still
be in an energy level above the ground state. Draw an energy-level
diagram for this process and find the energy of this resulting
excited state, assuming that we assign a...

An atom absorbs a photon with wavelength 500 nm and subsequently
emits a photon with wavelength 660 nm.
a) Determine the energy absorbed by the atom.
b) Assume that the atom is a solid particle with mass 3.3×10−26
kg and is initially at rest. Determine the speed of the atom after
it has emitted the photon, assuming that any additional energy it
acquired only contributed to its motion.
Can you do part b step by step, which equations are
required?

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 7 minutes ago

asked 8 minutes ago

asked 15 minutes ago

asked 19 minutes ago

asked 30 minutes ago

asked 35 minutes ago

asked 49 minutes ago

asked 49 minutes ago

asked 57 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago