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Be sure to answer all parts. The equilibrium constant Kc for the reaction below is 0.00180...

Be sure to answer all parts. The equilibrium constant Kc for the reaction below is 0.00180 at a certain temperature. Br2(g) ⇌ 2Br(g) If the initial concentrations are [Br2] = 0.0736 M and [Br] = 0.0751 M, calculate the concentrations of these species at equilibrium.

[Br2] = ___M

[Br] =____ M

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Answer #1


                  Br2 (g)   ------> 2 Br (g)

initially 0.0736                0.0751

at equili    (0.0736-x)          (0.0751 + 2x)

Kc = [Br-]^2/[Br2]

0.0018 = (0.0751 + 2x)/(0.0736-x)

x = -0.03745 M

At equilibrium,

[Br2] = (0.0736-(-0.03745)) = 0.1111 M

[Br-] = (0.0751+(2*(-0.03745)) = 0.0002 M

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