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C2H5OH + 3O2 --> 2CO2 + 3 H2O If the combustion uses 55.8 mL of oxygen...

C2H5OH + 3O2 --> 2CO2 + 3 H2O

If the combustion uses 55.8 mL of oxygen measured at 2.26 atm and 40 degrees Celsius, what volume of CO2 is produced when measured at STP?
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