A 10.0-L cylinder is filled with 19.0 grams of nitrogen dioxide gas (N2O) at 15.0°C. What is the pressure inside the cylinder?
Molar mass of NO2 = 1*MM(N) + 2*MM(O)
= 1*14.01 + 2*16.0
= 46.01 g/mol
mass of NO2 = 19.0 g
we have below equation to be used:
number of mol of NO2,
n = mass of NO2/molar mass of NO2
=(19.0 g)/(46.01 g/mol)
= 0.413 mol
we have:
V = 10.0 L
n = 0.413 mol
T = 15.0 oC
= (15.0+273) K
= 288 K
we have below equation to be used:
P * V = n*R*T
P * 10 L = 0.413 mol* 0.0821 atm.L/mol.K * 288 K
P = 0.977 atm
Answer: 0.977 atm
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