Question

For the following: PCl5(g) --> PCl3(g) + Cl2(g) The initial concentration of PCl5(g) is 2M and...

For the following: PCl5(g) --> PCl3(g) + Cl2(g)

The initial concentration of PCl5(g) is 2M and at equilibrium the concentration is Cl2(g) is 0.3M. Calculate the value of K.

K =

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Answer #1

Concentration of PCl5 intially = 0.237/3.7 = 0.064M    

                               PCl5->-------------> PCl3 + Cl2

            at initial          2                        0         0

           At equilibrium 2- x                   x         x

but x= [Cl2]= 0.3 from data

                                               Kc = [PCl3][Cl2 ]/[PCl5]

                                                = x2/ 2- x    

                                               = 0.3 x0.3/1.7

             Kc= 0.0529 mol/lit

                                                   

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