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The heat of fusion of ice is 6.00 kJ/mol. Find the number of photons of wavelength...

The heat of fusion of ice is 6.00 kJ/mol. Find the number of photons of wavelength = 7.35×10−6 m that must be absorbed to melt 6.20 g of ice.

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Answer #1

E = hc/

h = 6.625*10^-34Joule-sec

C   = 3*10^8m/sec

    = 7.35*10^-6 m

E   = 6.625*10^-34*3*10^8/7.35*10^-6   = 2.7*10^-20 J/photons

no of moles of ice   = W/G.M.Wt

                               = 6.2/18   = 0.34moles

q   = n*Hf

     = 0.34*6   = 2.04KJ     = 2040J

no of photons   = 2040J/2.7*10^-20J/photons    = 7.55*10^22 photons >>>>>answer

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