A 2.5 mol sample of ideal gas initially at 1 atm and 25 °C is expanded isothermally (ΔT = 0) and reversibly to twice its original volume.
What is the change in internal energy?
For isothermal expansion
Change in internal energy(∆U) =0
For isothermal process
Work done(w) = - nRTln(2V1/V1)
= -( 2.5 mole × 8.314(J/mol K ) × 298.15K × ln(2)
= - ( 2.5mole × 8.314(J/mol K ) × 298.15K ×2.303log(2)
= - 4296.2J
According to first law of thermodynamics
∆U = q + w
∆U =0
q + w = 0
q = -w
q = - ( -4296.2J)
= + 4296.2J
So , 4296.2J of heat is added to the system and all the added heat converted to work
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