Consider a 0.91 M solution of each of the following
salts. will each solution be acidic neutral of basic:
ch3ch2nh3oi
(ch3)3nhi
nh4ch3coo
Rbch3coo
1) CH3CH2NH3+ ----------------------> CH3CH2NH2 + H+ . so it is acidic salt
2) (CH3)3NH+ --------------------> (CH3)3N + H+ . it is releasing H+ ion so it is also acidic salt
3) CH3COONH4+ ----------------------> neutral
because it is the salt of weak acid CH3COOH and weak base NH4OH
4) CH3COORb ---------------------> it is basic salt
because anion participate in hydrolysis gives basic nature to the solution
CH3COO- + H2O --------------------> CH3COOH + OH-
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