Question

Compound Amount Volume of benzaldehyde (mL) 0.080 Volume of acetone (mL) 0.029 Volume of NaOH catalyst...

Compound

Amount

Volume of benzaldehyde (mL)

0.080

Volume of acetone (mL)

0.029

Volume of NaOH catalyst solution (mL)

1.000

Mass of filter paper without product (g)

0.1396

Mass of filter paper with product (g)

0.2038

Calculate the Theoretical Yield and Percent Yield. Show calculations.

limiting reagent is acetone

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
I need all the numbers to be converted to mL/g , mL , or g having...
I need all the numbers to be converted to mL/g , mL , or g having all the answere round to 3 significant figures and not to have any ul, mg or ul/mg. Thanks! mMol benzaldehyde: (80 µl x 1.044mg/1µL)x (1mMol/106.121 mg ) = 0.79 mMoL benzaldehyde. mMol of acetone = 29 µl X (0.79 mg / 1mL) X (1mMol/ 58.08 mg) = 0.39 mMol acetone Limiting reagent: 0.79 mMol benzaldehyde X (1 mMol of dibenzalacetone /2 mMol benzaldehyde) =...
CoCl2.6H2O + H2C2O4.2H2O -> CoC2O4.4H2O + 2 HCl + 4 H2O If, according to previously provided...
CoCl2.6H2O + H2C2O4.2H2O -> CoC2O4.4H2O + 2 HCl + 4 H2O If, according to previously provided equation, the reaction uses 2.00 g of cobalt (II) chloride hexa hydrate and 1.26 g of  oxalic acid dihydrate, and the amount of cobalt oxalate tetrahydrate product actually collected is determined according to the following information: * Mass of watch glass: 50.73 g * Mass of filter paper: 0.38 g * Mass of watch glass, filter paper and product: (5.22x10^1) g, what is the percent...
preparation of acetylsalicyclic acid post lab question 4.52 grams of salicylic acid and 4.5 mL of...
preparation of acetylsalicyclic acid post lab question 4.52 grams of salicylic acid and 4.5 mL of acetic anhydride (density: 1.080 g/mL) are mixed together. 3.75 grams of acetylsalicylic acid are obtained in the reaction. 1.) What is the limiting reagent in this reaction? And Why? 2.) What is the theoretical yield of the reaction? Show the calculations. 3.) What is the percent yield of the reaction? Show the calculations
A nickel coordination compound, Ni(NH3)6CL2, can be prepared by a procedure similar to the one you...
A nickel coordination compound, Ni(NH3)6CL2, can be prepared by a procedure similar to the one you will use to prepare Cu(NH3)4SO4 H20. the reaction can be represented stoichiometrically as NiCl2 6H20 + 6 NH4OH rightarrow Ni (NH3)6Cl2 + 12H20 4.850g of NiCl2 6H20 is treated with 22.0 mL of 15M NH40H solution. 4.230g of product is obtained What is the limiting reagent? What is the ratio (moles NH3/moles Ni2+) in solution? Calculate theoretical yield and percent yield.
A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M...
A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M ammonia solution at ice temperature, and carbon dioxide is bubbled in. Assume that sodium bicarbonate is formed until the limiting reagent is entirely used up. The solubility of sodium bicarbonate in water at ice temperature is 0.75 mol per liter. Also assume that all the sodium bicarbonate precipitated is collected and converted quantitatively to sodium carbonate The mass of sodium chloride in (g) is...
A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M...
A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M ammonia solution at ice temperature, and carbon dioxide is bubbled in. Assume that sodium bicarbonate is formed until the limiting reagent is entirely used up. The solubility of sodium bicarbonate in water at ice temperature is 0.75 mol per liter. Also assume that all the sodium bicarbonate precipitated is collected and converted quantitatively to sodium carbonate The mass of sodium chloride in (g) is...
1). The volume of a stock 6 M NaOH solution required to prepare 250 mL of...
1). The volume of a stock 6 M NaOH solution required to prepare 250 mL of a 1 M NaOH solution. 2). The mass of potassium hydrogen phthalate (KHP) required to react with 25 mL of a 1 M NaOH solution. The molecular weight of KHP is 204.23 g/mol. 3). The amount of water required to dissolve the quantity of KHP calculated in (b), given that the solubility of KHP is 10.2 grams per liter.
A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M...
A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M ammonia solution at ice temperature, and carbon dioxide is bubbled in. Assume that sodium bicarbonate is formed until the limiting reagent is entirely used up. The solubility of sodium bicarbonate in water at ice temperature is 0.75 mol per liter. Also assume that all the sodium bicarbonate precipitated is collected and converted quantitatively to sodium carbonate The mass of sodium chloride in (g) is...
Calculate the theoretical yield of the solid precipitate. Show your work. mass of CaCl2 =2.0 g...
Calculate the theoretical yield of the solid precipitate. Show your work. mass of CaCl2 =2.0 g Molar mass of CaCl2 = 110.98 g/mol Moles of CaCl2 = 2.0 g * 1 mol/110.98g = 0.018 mol Mass of K2Co3 =2.0 g Molar mass of K2Co3 = 138.205 g/mol Moles of K2Co3 =2.0 g * 1 mol/ 138.205g =0.0145 moles According to balanced equation 1mole of CaCl2 reacts with 1 mole of K2CO3 Thus, 0.018 moles of CaCl2 will react with =...
NH3/NH4 buffer: Mass NH4Cl used 1.3738g volume NaOH used 21.2 ml initial pH (0f the buffer)...
NH3/NH4 buffer: Mass NH4Cl used 1.3738g volume NaOH used 21.2 ml initial pH (0f the buffer) 9.6, pH after 1 drop HCl 9.03, pH after 10 drops HCl 8.91 Dilute NaOH solution Initial pH 10.35 pH :1 drop HCl 10.21, 10 drops HCl 2.85 Acetate buffer (0.500) Mass of CH3COONa * 3H2O 10.935 volume CH#COOH 44.3 ml initial pH 4.89 1.0 ml of NaOH pH 4.93 initial volume 2.2 final volume 16.2 final pH 5.91 Acetate buffer (0.100) Mass of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT