Question

Im taking a course to review general chemistry. In lecture, my professor didnt say how to work this kind of problem in the homework. Please list all the steps. Thanks.

The heat of fusion of water is 79.9 cal/g, the heat of vaporization of water is 540 cal/g, and the specific heat of water is 1.00 cal/deg/g. How many grams of ice at 0 ° could be converted to steam at 100 °C by 9,958 cal of heat?

Answer #1

Q = m c ∆T

Q = quantity of heat in joules (J)

m = mass of the substance acting as the environment in

grams (g)

c = specific heat capacity (4.19 for H2O) in J/(g
^{o}C)

∆T = change in temperature = Tfinal - Tinitial in ^{o}C

specific heat (c) = Heat Energy / (mass of substance * change in temperature)

The "cold water" in this case is going to do three things:

a) icewill melt

b) as a liquid, the temperature goes up 100 °C

c) Liquid has to convert to steam

Let us keep w is weight of water .

w x 79.9 /18 + w x 1 x 100 + w x 540 /18 = 9,958

4.438 w + 100 w + 30 w = 9958

134.438 w = 9958

**w = 74.07 gm**

**Weight of water is 74.07 gm**

The heat of fusion of water is 79.9 cal/g, the heat of
vaporization of water is 540 cal/g, and the specific heat of water
is 1.00 cal/deg/g. How many grams of ice at 0 ° could be converted
to steam at 100 °C by 9,076 cal of heat?

17 grams of ice at –36°C is to be changed to steam at 178°C. The
entire process requires _____ cal. Round your answer to the
nearest whole number. The specific heat of both ice
and steam is 0.5 cal/g°C. The specific heat of water is 1.00
cal/gK. The heat of fusion is 80 cal/g and the heat of vaporization
is 540 cal/g.

10.0g of ice at -0.50c is placed into a 100g aluminum cup at
300C. the latent heat of vaporization of water is 540 cal/g. the
latent of fusion of water is 80 cal/g. the specific heat of water
is 1.00 cal/gC. the specific heat of ice is 0.500cal/gC. the
specific heT of steam is 0.216 cal/gC. which of the following
sutuations is correct
A) T(equil)=97C with 10.0g of water
B) t(equil)=100C w/4.6g steam
C) t(equil)=152C w/10g steam
D) T(equil)=100C w/6.4g...

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