From the balanced molecular equations, write the complete ionic and net ionic equations for the following. (Use the lowest possible whole number coefficients. Include states-of-matter under the given conditions in your answer.)
a)CaCO3(s) + H2SO4(aq) → CaSO4(s) + CO2(g) + H2O(l) *Need complete ionic and net ionic equations
b)K2C2O4(aq) + Cd(OH)2(aq) → 2 KOH(aq) + CdC2O4(s) *Need complete ionic and net ionic equations
c)Zn(NO3)2(aq) + H2SO4(aq) → ZnSO4(s) + 2 HNO3(aq) *Need complete ionic and net ionic equations
a) Molecular equation :-
CaCO3(s) + H2SO4 (aq) ------> CaSO4(s) + CO2(g) + H2O(l)
Ionic equation:-
CaCO3(s) + 2H^+(aq) + SO4^2-(aq) -----> CaSO4(s) + CO2(g) + H2O(l)
Net ionic equation :- There is no spectator ions hence net ionic equation will be same as ionic equation
b) Molecular equation :-
K2C2O4(aq) + Cd(OH)2(aq) ----> 2 KOH(aq) + CdC2O4(s)
Ionic equation:-
2 K^+(aq) + C2O4^2-(aq) + Cd^2+(aq) + 2 OH^-(aq) ----> 2K^+(aq) + 2 OH^-(aq) + CdC2O4 (s)
Net ionic equation :- cancel out same ions from ionic equation
C2O4^2-(aq) + Cd^2+(aq) -----> CdC2O4 (s)
c) Molecular equation :-
Zn(NO3)2(aq) + H2SO4(aq) ------> ZnSO4(s) + 2HNO3(aq)
Ionic equation :-
Zn^2+(aq) + 2NO3^-(aq) + 2H^+(aq) + SO4^2-(aq) ----> ZnSO4(s) + 2H^+(aq) + 2NO3^-(aq)
Net ionic equation :- Cancel out same ions from Ionic equation
Zn^2+(aq) + SO4^2-(aq) ----> ZnSO4 (s)
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