2. Calculate the mass of each of the following volumes.
a) 20 L of chlorine gas
b) 1,500 mL of sulfur trioxide gas
c) 3.77 L of carbon monoxide gas
Molar mass of Cl2 = 70.9 g/mol
Molar mass of SO3 = 80.1 g/mol
Molar mass of CO = 28.0 g/mol
At Standard Temperature and Pressure mass of 22.4L of 22400 mL of gas is equal to its gram molar mass.
(a) Hence, mass of 22.4L of Cl2 gas = 70.9 g
So, mass of 20L of Cl2 gas = 20 x 70.9 / 22.4
= 63.3 g of Cl2.
(b) mass of 22400 L of SO3 gas = 80.1 g
So, mass of 1500 mL of SO3 gas = 1500 x 80.1 / 22400
= 5.36 g of SO3.
(c) mass of 22.4L of CO gas = 28.0 g
So, mass of 3.77L of CO gas = 3.77 x 28.0 / 22.4
= 4.71 g of CO2.
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