Question

Carbon disulfide (CS2) reacts with excess chlorine (Cl2) to produce carbon tetrachloride (CCl4) and disulfur dichloride (S2Cl2). If 45.2 g of CS2 yields 78.5 g of CCl4, what is the percent yield? (Hint, you must first write the balanced equation.)

Answer 1

The balanced reaction is :

CS₂ + 3 Cl₂ --> CCl₄ + S₂Cl₂

Therefore, one mole of CS₂ produces one mole of CCl₄.
If 45.2 g of CS₂ yields 78.5 g of CCl₄, what is the percent yield?

no. of moles of CS₂ = 45.2 g CS₂ * (1 mol CS₂/ 76.139 g CS₂)

= 0.59365 moles

Therefore, theoretical no. of moles of CCl₄ = 0.59365 moles

Theoretical Yield = 0.59365 moles * (153.82 g CCl₄/ 1 mol CCl₄) = 91.315 g CCl₄

Percent Yield = (Experimental yield/Theoretical yield) * 100% = ( 78.5 g CCl₄/ 91.315 g CCl₄) * 100% = 86%

Hence, the Percent Yield = 86%