Question

A reaction R --> P has the rate constant, k1 = 2.52 x 10-3 s-1 at...

A reaction R --> P has the rate constant, k1 = 2.52 x 10-3 s-1 at 80.0 °C, and activation energy, Ea = 54.6 kJ.mol-1. At 110 °C, what is new rate constant, k2?

4.48 x 10^8

1.33 x10^-3

1.33 x 10^8

1.08 x 10^-1

1.08 x 10^-2

Science   Chemistry   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

this is the temperature dependent equation for rate constant

k = ko e^(-Ea/RT)

Given

Ea = 54.6 KJ/mol = 54600 J/mol

T1 = 80 C = 80 + 273 = 353 K

k1 = 2.52 * 10-3 s-1

T2 = 110 C = 273 + 110 = 383 K

k2 = ?

R = 8.314 J/mol.K

k1 / k2 = ko e^(-Ea/RT1) / ko e^(-Ea/RT2)

k1 / k2 = e^(-Ea/RT1) / e^(-Ea/RT2) = e^(-Ea/RT1+Ea/RT2)

sub known values

2.52 * 10-3 s-1 / k2 = e^( - (54600 / (8.314 J/mol.K *353 K) ) + (54600 / (8.314 J/mol.K *383 K) ) )

2.52 * 10-3 s-1 / k2 = e^(-1.457)

2.52 * 10-3 s-1 / k2 = 0.2329

k2 = 1.08 * 10-2 s-1 Answer

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider a consecutive reaction with pre-equilibrium: A + B ? X ? Z;    The rate...
Consider a consecutive reaction with pre-equilibrium: A + B ? X ? Z;    The rate constant for each step is k1, k-1 and k2, respectively. (b)Derive the expression for the observed activation energy in term of Ea1, Ea-1 and Ea2. (c)Based on your results, sketch the different scenarios for the possible Arrhenius plots for this type of mechanism. (question is from physical chemistry course)
The rate constant of a chemical reaction increased from 0.100 s−1 to 3.10 s−1 upon raising...
The rate constant of a chemical reaction increased from 0.100 s−1 to 3.10 s−1 upon raising the temperature from 25.0 ∘C to 51.0 ∘C . Part A Calculate the value of (1/T2−1/T1) where T1 is the initial temperature and T2 is the final temperature. Express your answer numerically. Part B Calculate the value of ln(k1/k2) where k1 and k2 correspond to the rate constants at the initial and the final temperatures as defined in part A. Express your answer numerically....
The Arrhenius equation shows the relationship between the rate constant k and the temperature T in...
The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at two different absolute...
± The Arrhenius Equation The Arrhenius equation shows the relationship between the rate constant k and...
± The Arrhenius Equation The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction...
The rate constant of a first-order reaction is 0.0032 x 10-4 L/mol *s at 640 K....
The rate constant of a first-order reaction is 0.0032 x 10-4 L/mol *s at 640 K. If the activation energy is 176,406J/mol, calculate the temperature at which is rate constant is 0.0039 x10 -4 L/mol*s. Show your work please.
The Arrhenius equation shows the relationship between the rate constant k and the temperature Tin kelvins...
The Arrhenius equation shows the relationship between the rate constant k and the temperature Tin kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), Ais a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at two different absolute temperatures (T1and...
The rate constant of a chemical reaction increased from 0.100 s−1 to 2.60 s−1 upon raising...
The rate constant of a chemical reaction increased from 0.100 s−1 to 2.60 s−1 upon raising the temperature from 25.0 ∘C to 45.0 ∘C . I solved (1T2−1T1) = −2.11×10−4   K−1 In (k1/k2) = -3.26 But, I'm having problems on this question: What is the activation energy of the reaction? Express your answer numerically in kilojoules per mole. It would be great if you could show all of your work. I've been trying to figure out this problem for a...
If a first order reaction has a rate constant of 4.15 X 10-2 s-1 at a...
If a first order reaction has a rate constant of 4.15 X 10-2 s-1 at a temperature of 24.5oC, what would the value of k be if the reaction temperature was changed to 52oC given that the activation energy is 67.8 kJ/mol?
± The Arrhenius Equation The Arrhenius equation shows the relationship between the rate constant k and...
± The Arrhenius Equation The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k=Ae−Ea/RT where R is the gas constant (8.314 J/mol⋅K), A is a constant called the frequency factor, and Eais the activation energy for the reaction. However, a more practical form of this equation is lnk2k1=EaR(1T1−1T2) which is mathmatically equivalent to lnk1k2=EaR(1T2−1T1) where k1 and k2 are the rate constants for a single reaction at...
The rate constant of a reaction is 6.7 × 10−3 s−1 at 25°C, and the activation...
The rate constant of a reaction is 6.7 × 10−3 s−1 at 25°C, and the activation energy is 33.6 kJ/mol. What is k at 75°C? Enter your answer in scientific notation.
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT