10) a bullet weighs 235 grams (1 grain= 0.0648g) moving at 2520 ft/s. Calculate Kinetic energy in J. 2.54cm =1 in
Kinetic energy , KE = (1/2) mv2
Where
m = mass of bullet = 235 g x ( 10-3 kg/g) = 235 x10-3 kg
v = velocity of bullet = 2520 (ft/s) x (1m /3.28 ft) = 768.3 m/s
Plug the values we get KE = (1/2)x(235 x10-3 kg) x ( 768.3 m/s)2
= 69.3 x103 J
Get Answers For Free
Most questions answered within 1 hours.