Calculate the osmotic pressure of a solution containing 17.05 mg of hemoglobin in 14.1 mL of solution at 35 ∘C . The molar mass of hemoglobin is 6.5×104 g/mol.
Formula: = CST
Where is the osmotic pressure of solution, C = concentration of solution = (mass/molar mass)*1000/volume (mL)
mass = 17.05 mg = 17.05*10-3 g, molar mass = 6.5*104 g mol-1 and volume = 14.1 mL
i.e. C = {17.05*10-3 g/(6.5*104 g mol-1)} * 1000/14.1 L = 0.186*10-4 mol/L
S = universla solution constant = 0.0821 L atm mol-1 K-1
T = Absolute temperature = 35 oC = (35 + 273.15) K = 308.15 K
Now, = 0.186*10-4 mol/L * 0.08206 L atm mol-1 K-1 * 308.15 K
i.e. = 4.704*10-4 atm
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