Question

Calculate the osmotic pressure of a solution containing 17.05 mg of hemoglobin in 14.1 mL of solution at 35 ∘C . The molar mass of hemoglobin is 6.5×104 g/mol.

Answer 1

Formula: = CST

Where is the osmotic pressure of solution, C = concentration of solution = (mass/molar mass)*1000/volume (mL)

mass = 17.05 mg = 17.05*10^-3 g, molar mass = 6.5*10⁴ g mol^-1 and volume = 14.1 mL

i.e. C = {17.05*10^-3 g/(6.5*10⁴ g mol^-1)} * 1000/14.1 L = 0.186*10^-4 mol/L

S = universla solution constant = 0.0821 L atm mol^-1 K^-1

T = Absolute temperature = 35 ^oC = (35 + 273.15) K = 308.15 K

Now, = 0.186*10^-4 mol/L * 0.08206 L atm mol^-1 K^-1 * 308.15 K

i.e. = 4.704*10^-4 atm