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If I start out with 50.0 mLs of solution, then take a 25.0 mL aliquout of...

If I start out with 50.0 mLs of solution, then take a 25.0 mL aliquout of the solution, and I dilute the 25.0 mL aliquot to 50.0 mLs; how would I use this dilution infromation to determine the concentration of the initial 50.0 mL solution?

For example, the concentration after the aliquot was diluted to 50.0 mLs was 1.9065 x 10-5. What was the concentration of the original 50.0 mL solution?

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Homework Answers

Answer #1

Use the formula C1V1 = C2V2

Where C1 = initial concentration = ?

V1 = initial volume = 25 ml (volume of aliquot)

C2 = final concentration = 1.9065 10-5 (concentration after silution)

V2 = final concentration = 50 ml (volume after dillution)

Substitute the value in formula

C1V1 = C2V2

C1 = C2V2/V1

= 1.9065 10-5   50 / 25

C1 = 3.813 10-5

original solution concentration is 3.813 10-5

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