Question

Question from Recrystallization Lab (Organic Chemistry):

Two crystallized compounds X and Y have the same solubility ratio in water (solubility = 1g/100 mL at 20

Answer 1

A. Solubility of Compound Y at 20 ^oC is 1g/100 mL.

So to keep the 1 g of Y in solution the minimum volume of solution will be 100 mL.

Solubility of compound X at 20 ^oC is 1g/100 mL.

So, amount of X dissolved in 100 mL solution is 1 g.

Hence, amount of pure X obtained is (10-1)g = 9g

B. Solubility of Compound Y at 20 ^oC is 1g/100 mL.

So to keep the 8 g of Y in solution the minimum volume of solution will be (100*8) mL = 800 mL

Solubility of compound X at 20 ^oC is 1g/100 mL.

So, amount of X dissolved in 800 mL solution is (800/100) g = 8 g.

Hence, amount of pure X obtained is (10-8) g = 2g.