You have determined that the solubility product Ksp of Herbigon is 8.50
Herbigon is a herbicide used in the agriculture.
XAc + HAc ----> X- + H+ + Ac (Ac = acetate ion, CH3COO-)
ICE Table:
XAc
HAc
X
H Ac
initial conc.....................1M .............0............
0.......... 0
change...........................-x............+0.002.......+x.....
x+0.002
final...............................1-x ............0.002.......
x...... x+0.002
Now,
Ka = antilog(pKa) = 10-4.76 =
1.74x10-5.
Ka = [H+][Ac]/[HAc]
Ka = x(x+0.002)/(1-x) (assume x<<0.002,1)
1.74 x 10-5 = x x 0.002
x = 0.0087 M
pH= -log[H+]
pH = -log(0.0087) = 2.06
Get Answers For Free
Most questions answered within 1 hours.