Question

the following data were obtained for the reaction, 2NO2(g)-->2NO (g) + O2. Times   (NO2) 0   0.8333...

the following data were obtained for the reaction, 2NO2(g)-->2NO (g) + O2.

Times   (NO2)

0   0.8333

20   0.4167

40   0.2778

60   0.2083

c) what is the reaction order with respect to NO2? explain

D) write the rate law for this equation

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Homework Answers

Answer #1

From the given data, calculate the rate of reaction

Rate of reaction = [NO2] / Time

For 20 s, rate of reaction = 0.4167/20 = 0.020835 mol L-1 s-1

Similarly,

Time (s) [NO2], M Rate of reaction M/s
0 0.8333 ---
20 0.4167 0.020835
40 0.2778 0.006945
60 0.2083 0.003472

Predicted rate law = k [NO2]m

Rate1 / rate2 = [NO2]m1 / [NO2]m2  

0.020835/0.006945 = (0.4167)m / (0.2778)m

3 = 3m

m =1

Order with respect to NO2 = 1 (first order)

Rate law = k [NO2]

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