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The following data were measured for the reaction BF3(g)+NH3(g)→F3BNH3(g): Experiment [BF3](M) [NH3](M) Initial Rate (M/s) 1...

The following data were measured for the reaction BF3(g)+NH3(g)→F3BNH3(g):

Experiment [BF3](M) [NH3](M) Initial Rate (M/s)
1 0.250 0.250 0.2130
2 0.250 0.125 0.1065
3 0.200 0.100 0.0682
4 0.350 0.100 0.1193
5 0.175 0.100 0.0596

Part D What is the rate when [BF3]= 0.150 M and [NH3]= 0.530 M ?

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Answer #1

see experiment 1 and 2:
[NH3] becomes half and [BF3] constant, rate also become half
So, order of NH3 is 1

see experiment 3 and 4:
[NH3] constant and [BF3] becomes 1.75 times, rate also becomes 1.75 times
So, order of [BF3] is 1

rate = k [BF3] [NH3]

to find k put values from experiment 1

rate = k [BF3] [NH3]
0.2130 = k * 0.250 * 0.250
k = 3.408

so,
rate = 3.408 * [BF3] [NH3]

D)
put given values

rate = 3.408 * [BF3] [NH3]
rate = 3.408 *0.150*0.530
= 0.271 M/s

Answer: 0.271 M/s

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