Question

The Champagne site is 1650m below sea level. The temperature of the fluid being emitted from the summit was 103 degrees Celsius. What is the pressure at this depth? What is the expected phase of CO2 under these conditions? please show all work

Answer 1

Given Height of the Champagne site (h) = 1650m and the temperature (T) = 103^oC

Fluid Pressure and depth relation is P = r*g*h

where r(rho) density of fluid in this case sea water.i.e.= 1.03*10³ kg/m³

and the atmospheric pressure is 1.01 x 10⁵ N/m² also given g which is the acceleration of gravity =9.8m/s²

Fluid Pressure and depth relation is P_fluid = r*g*h =(1.03*10³ kg/m³ )*(9.8m/s²)*1650m = 1.66 *10⁷ Newton/m²

P_total = P_atmosphere + P_fluid =​ 1.01*10⁵ +1.66*10⁷ Pa = 1.67*10⁷ Pa = 1.67*10⁴ KPa

Pressure at the depth = 1.66*10⁷ Pa and the phase of CO₂ is in Supercritical state which is the fluid above critical temperature and pressure