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How many milliliters of acetylene (ethyne) gas at 25 degrees C and 1 atmosphere pressure would...

How many milliliters of acetylene (ethyne) gas at 25 degrees C and 1 atmosphere pressure would be produced from the reaction CaC2+2H20-->C2H2+Ca(OH)2 if 2.0 g of calcium carbide is the limiting reactant

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Answer #1

Since 2.0 grams of CaC2 it's our limiting reagent, we can start by converting that into moles using molar mass of CaC2:

The balanced equation, based on the stoichiometric coefficients says that per 1 mole of calcium carbide (CaC2)that reacts, 1 mole of acetylene (C2H2) is produced. So per 0.0312 moles of CaC2that reacts, 0.0312 mole of C2H2 is produced.

In order to find the volume in mililiters (mL) we should use the ideal gas law, with the amount of moles n=0.0312 mol, Universal constant R=0.082 atm.L/(mol.K), temperature T=(25+273) K, pressure P=1 atm

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