How will each of the following changes affect an equilibrium mixture of reactants and products? Answer with increase, decrease, to the left, to the right
Fe^3+ + HSCN = Fe(SCN)^2+ + H^+
Shift direction |
[Fe^3+] |
[HSCN] |
[Fe(SCN)^2+] |
[H^+] |
|
Add Fe^3+ |
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Add HSCN |
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Ass HNO3 |
Changes in concentration do no change the value of Keq as long as the temperature remains constant. Please explain.
1. On adding Fe3+, equilibrium will shift to the right. [Fe3+] will increase, [HSCN] will decrease, [Fe(SCN)2+] and [H+] will increase.
2. On adding HSCN, equilibrium will shift to the right. [Fe3+] will decrease, [HSCN] will increase, [Fe(SCN)2+] and [H+] will increase.
3. HNO3 ionises to give H+ and (NO3)- and its effect is governed by common ion effect. Since [H+] appears on right hand side of the equation, therefore on adding HNO3 equilibrium will shift to the left. [Fe3+] will increase, [HSCN] will increase, [Fe(SCN)2+] will decrease and [H+] will increase.
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