Question

A 314 gram sample of water at 67.5 degree Celsius loses 9.60e+03 J of heat. Calculate...

A 314 gram sample of water at 67.5 degree Celsius loses 9.60e+03 J of heat. Calculate the final temperature of the water. ___ degrees Celcius

Homework Answers

Answer #1

q = mass of water specific heat of H2O(l)  T

then T = q / ( mass of water   specific heat of H2O)

Substitute value in above equation

T = 9600 / (314 4.184) = 7.30

water lose heat therefore it temprature decreases by 7.30 0C

Final tempreture of water = 67.5 - 7.30 = 60.2  0C

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