For the reaction, shown below, determine which statements are True and which are False.
3Fe(s) + Cr2O72-(aq) +14H+(aq) → 3Fe2+(aq) + 2Cr3+(aq) + 7H2O(l) ξo=1.77V
True False The oxidation state of chromium in dichromate
is +6.
True False The oxidizing agent is Cr3+
(aq)
True False The reducing agent is Cr3+
(aq)
True False The iron half-reaction takes place in an
acidic solution.
True False The lowest oxidation state for hydrogen in
this reaction is 0
True False The oxidation state of oxygen changes from -2
to 0.
If necessary, separate this into two half reactions to determine the oxidizing and reducing agents. Oxidation states can be calculated by remembering that oxygen usually has an oxidation state of 2-, except in O=O or O-O bonds. Hydrogen usually has an oxidation state of 1+, except in H2. |
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True False The oxidation state of chromium in
dichromate is +6.
Cr2O7 = -2
2Cr + 7(-2) = -2
Cr =( -2 + 14 )/(2)
Cr = +6
this is true
True False The oxidizing agent is Cr3+ (aq)
oxidizing agent must be REDUCED, in this case, Cr is not even in
the reagents, so this is FALSE
True False The reducing agent is Cr3+ (aq)
False, it is in the products, sides, agents are present only on the left
True False The iron half-reaction
takes place in an acidic solution.
Not likely, sinc eFe(s) = Fe+2 + e2- ,requires on O, OH, H2O, H+
balance
True False The lowest oxidation
state for hydrogen in this reaction is 0
false, it is +1, and won't change
True False The oxidation state of oxygen changes from -2 to 0.
false, since O remains with -2 charge always
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