Question

436 mL of 0.710 M iron(III) hydroxide is exactly neutralized with 0.540 M carbonic acid solution. What volume of acid solution is required?

__________ mL

Answer 1

we have the Balanced chemical equation as:

2 Fe(OH)3 + 3 H2CO3 ---> Fe2(CO3)3 + 6 H2O

Here:

M(Fe(OH)3)=0.71 M

M(H2CO3)=0.54 M

V(Fe(OH)3)=436.0 mL

According to balanced reaction:

3*number of mol of Fe(OH)3 =2*number of mol of H2CO3

3*M(Fe(OH)3)*V(Fe(OH)3) =2*M(H2CO3)*V(H2CO3)

3*0.71 M *436.0 mL = 2*0.54M *V(H2CO3)

V(H2CO3) = 860. mL

Answer:  860. mL