A buffer solution is prepared by mixing 26.6 mL of 0.0746 M ascorbic acid with 77.5 mL of 0.736 M sodium ascorbate.
1. Calculate the pH (to two decimal places) of this
solution.
Assume the 5% approximation is valid and that the volumes are
additive.
2. Calculate the pH (to two decimal places) of the buffer
solution after the addition of 0.0647 g of sodium ascorbate
(NaC5H7O4COO) to the buffer
solution above.
Assume 5% approximation is valid and that the volume of solution
does not change.
1)
millimoles of ascorbic acid = 26.6 x 0.0746 = 1.984
millimoles of sodium ascorbate = 77.5 x 0.736 = 57.04
ascorbic acid pKa = 4.2
pH = pKa + log [salt / acid]
= 4.2 + log [57.04 / 1.984]
= 5.66
pH = 5.66
2)
millimoles of sodium ascorbate (C) = 0.0647 / 198.1 = 3.266 x 10^-4
= 0.3266 millimoles
pH = pKa + log [salt + C / acid - C ]
= 4.20 + log [57.04 + 0.3266 / 1.984 - 0.3266]
= 2.66
pH = 2.66
Get Answers For Free
Most questions answered within 1 hours.