Question

Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH(aq).NaOH(aq). Calculate the amount of Ga(s)Ga(s) that can be deposited from a Ga(III)Ga(III) solution using a current of 0.380 A0.380 A that flows for 30.0 min.30.0 min.

Answer 1

Sol.

Reaction :

Ga3+(aq) + 3e- -----> Ga(s)

As Current = I = 0.380 A

Time = t = 30 min = 30 × 60 s = 1800 s

Faraday's constant = F = 96500 C / mol

Number of electrons transferred = Z = 3

So , Number of moles of Ga(s) that can be deposited

= n = It / ZF

= 0.380 × 1800 / ( 3 × 96500 )

= 0.00236 mol

As Molar Mass of Ga(s) = M = 69.723 g/mol

So , Mass of Ga(s) that can be deposited  

= m = nM  

= 0.00236 × 69.723  

=   0.1645 g