How many grams of hydrazine, N2H4, can be made from 10.39 g of N2 and excess H2?
Molar mass of N2 = 28.02 g/mol
mass(N2)= 10.39 g
number of mol of N2,
n = mass of N2/molar mass of N2
=(10.39 g)/(28.02 g/mol)
= 0.3708 mol
Balanced chemical equation is:
N2 + 2 H2 ---> N2H4 + 0
Molar mass of N2H4,
MM = 2*MM(N) + 4*MM(H)
= 2*14.01 + 4*1.008
= 32.052 g/mol
According to balanced equation
mol of N2H4 formed = (1/1)* moles of N2
= (1/1)*0.3708
= 0.3708 mol
mass of N2H4 = number of mol * molar mass
= 0.3708*32.05
= 11.89 g
Answer: 11.9 g
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