Question

When 0.100 mol of carbon is burned in a closed vessel with 8.00g of oxygen, how many grams of carbon dioxide can form? Which reactant is in excess, and how many grams of it remain after the reaction?

please show all work and step by step solution

Answer 1

Balanced chmical reaction is

C + O₂   CO₂

molar mass of O₂ = 32 gm/mole then 8 gm of O₂ = 8/32 = 0.25 mole

According to reaction 1 mole of carbon react with 1 mole of threfore to react with 0.100 mole of carbon required oxygen = 0.100 mole but oxygen given 0.25 mole therefore oxygen is excess reactant

oxygen is excess reactant

required oxygen for reaction = 0.100 mole given =0.25 mole excess oxygen = 0.25 - 0.10 = 0.15 mole

molar mass of O₂ = 32 gm/mole then 0.15 mole of O₂ = 0.15 X 32 = 4.8 gm

4.8 gm of oxygen remain after reaction

According to reaction 1 mole of carbon produce 1 molel of carbon dioxide therefore 0.100 mole of carbon will produce 0.100 mole of carbon dioxide

molar mass of CO₂ = 44.01 gm/mole then 0.100 mole of CO₂ = 0.100 X 44.01 = 4.401 gm

4.401 gm of carbon dioxide form