2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo’) for this reaction is +1.7 kJ/mol. If the cellular concentrations are 2PG = 0.5 mM and PEP = 0.1 mM, what is the free energy change at 37 oC for the reaction 2PG ↔ PEP?
5.8 kJ/mol
-5.8 kJ/mol
+2.4 kJ/mol
-2.4 kJ/mol
-4146.4 kJ/mol
+4146.4 kJ/mol
G = G0 + RTlnK
G0 = 1.7Kj/mole = 1700J/mole
R = 8.314J/mole-K
T = 37C0 = 37+273 = 310K
G = 1700+ 8.314*310ln0.1/0.5
= 1700+8.314*310*-1.6094
= -2447.97J/mole = -2.44797Kj/mole
= -2.4 kJ/mol >>>> answer
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