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If a saturated solution that is prepared by dissolving Ca(IO3)2 in water has [IO3] = 0.0131M,...

If a saturated solution that is prepared by dissolving Ca(IO3)2 in water has [IO3] = 0.0131M, what is the value of Ksp for calcium iodate, Ca(IO3)2?

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Answer #1

                                Ca(IO3)2 -->          Ca+2 +     2IO3-

Initial                         a                          0              0

At equilibrium          a-x                        x              2x

Given 2x = 0.0131

x = 6.55*10^-3

Ksp = [Ca+2][IO3-]2

       =(x)(2x)2

       = 4x3

          =1.124*10^-6 M3

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