If 9.76 moles of an ideal gas has a pressure of 1.84 atm, and a volume of 70.61 L, what is the temperature of the sample in degrees Celsius?
We have to use ideal gas equation here
the equation is PV=nRT
Where
Here
now rearrange the equation for T
PV=nRT
T = PV / nR
lets put the values in formula
T = (1.84 atm * 70.61 L) / 9.76 moles * 0.0821 atm L / mol K
T = 129.92 / 0.8013
T= 162.14 K
now we have to convert Kelvin to degrees Celsius
formula for this is
Kelvin = 273.15 + degrees Celsius
degrees Celsius= Kelvin - 273.15
degrees Celsius = 162.14 - 273.15
degrees Celsius =-111.01
So our final answer is -111.01 oC
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