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determine the molar solubility of AgBr in a solution containing 0.163M NaBr. Ksp(AgBr)=7.7x10^-13. I am really...

determine the molar solubility of AgBr in a solution containing 0.163M NaBr. Ksp(AgBr)=7.7x10^-13.

I am really struggling with this problem can some one please help me?

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Answer #1

NaBr -------------> Na+   + Br-

0.163                    0.163   0.163

AgBr --------------> Ag+   +   Br-

x                              x        0.163

Ksp = [Ag+][ Br-]

7.7x10^-13. = [Ag+] x 0.163

[Ag+] = 4.723 x10^-12

molar solubility = [Ag+] = 4.723 x10^-12M

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