Using MO theory, determine which of the species C2, N2, has the highest bond order and is paramagnetic. Show your orbital diagram and label all the orbirals.
B.O. = 1/2[bonding e- - antibonding e-]
C2 = 12e-
B.O. = 1/2[8-4] = 2
no unpaired e- is present in moleculer orbital electronic configuration so it is diamagnetic.
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N2 = 14e-
B.O. = 1/2[10-4] = 3
no unpaired e- is present in moleculer orbital electronic configuration so it is diamagnetic.
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