Question

The following information is given for n-pentane at 1 atm: Tb = 36.20°C Hvap(36.20°C) =  J/g Tm=...

The following information is given for n-pentane at 1 atm:

Tb = 36.20°C Hvap(36.20°C) =  J/g
Tm= –129.70°C Hfus(–129.70°C) =  J/g
Specific heat gas = 1.650 J/g °C
Specific heat liquid = 2.280 J/g °C

A 47.80 g sample of liquid n-pentane is initially at –30.50°C. If the sample is heated at constant pressure ( = 1 atm),  kJ of energy are needed to raise the temperature of the sample to 51.20°C.

______kJ

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