Given :
At 50 % transmittance path length is 10 cm
At 10 % transmittance , path length is unknown
Solution :
We use following equation :
% T = exp ( -abc) ….. 1
As we know a absorptivity and c is constant in this problem. Only change in transmittance.
Lets find out path length for 10 % transmittance.
50 = exp ( - 10 cm a x c )
Lets take ln of both side
Ln 50 = - 10 cm ac
3.91 = - 10 cm ac …..2
For transmittance
Ln 10 = - abc
2.30 = - abc … 3
Lets take a ratio of equation 2 and 3
3.91 / 2.30 = (- 10 cm ac )/ - abc
1.70 b = -10 cm
b = 5.89 cm
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