Question

Gaseous ethane CH3CH3 will react with gaseous oxygen O2 to produce gaseous carbon dioxide CO2 and gaseous water H2O . Suppose 0.30 g of ethane is mixed with 2.20 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to 2 significant digits.

Answer 1

equetion; 2CH₃CH_3(g)  + 7O_2(g) -----> 4CO_2(g) + 6 H₂O(g)

0.3 g 2.20 g (?)g

Ethane mol. mass=30 g

O₂  Mol. mass= 32 g

CO₂ mol. mass= 44 g

0.3 g Ethane is 0.3/30 = 0.01 mole ; 2.20 g O₂ is 2.20/32= 0.0687 mole

from equetion,1 mole Ethane required 3.5 mole O₂

so, 0.01 mole Ethane required= 0.01*3.5=0.035 mole O₂

we have enough amount of O_2, so, Ethane is limiting reagent

from equetion;

1 mole Ethane produce 2 mole CO₂

0.01 mole Ethane produce = 0.01*2= 0.02 mole CO₂ =0.88 g CO₂

given reaction produce 0.88 g Carbon dioxide