Consider the reaction shown. Using your knowledge of relative acid-base strengths and equilibrium, determine what you can about the size of Kc for the reaction.
HOCl(aq) + ClO3-(aq) <=> OCl-(aq) + HClO3(aq)
Solution: (Kc < 1)
In the given acid- base reaction,
HOCl(aq) + ClO3-(aq) == OCl-(aq) + HClO3(aq)
Kc = [OCl-] [HClO3] / [HOCl] [ClO3-]
>>HOCl is a weak acid hence, its conjugate base OCl- is strong base while HClO3 is a strong acid hence, it's conjugate base ClO3- is a weak base.
Thus, a weak acid and weak base reaction can not go towards completion, hence the concentrations of HOCl and ClO3- is high, therefore quilibrium is always shifted towards reactant side.
Hence, Kc < 1
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