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Calculate ΔrG° for the reaction below at 25.0 °C CH4(g) + H2O(g) → 3 H2(g) +...

Calculate ΔrG° for the reaction below at 25.0 °C
CH4(g) + H2O(g) → 3 H2(g) + CO(g)
given ΔfG° [CH4(g)] = –50.8 kJ/mol, ΔfG° [H2O(g)] = –228.6 kJ/mol, ΔfG° [H2(g)] = 0.0 kJ/mol, and ΔfG° [CO(g)] = –137.2 kJ/mol.

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Answer #1

ΔrG° reaction = ΔrG° products - ΔrG° reactants

                      = ( 3 x 0 -137.2) - ( -50.8 -228.6)

                      = -137.2 + 279.4

                      = 142.2 kJ / mol

ΔrG° reaction = 142.2 kJ / mol

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