Question

Here is the combustion reaction for octane (C8H18), which is a primary component of gasoline. How...

Here is the combustion reaction for octane (C8H18), which is a primary component of gasoline. How many moles of CO2 are emitted into the atmosphere when 24.1 g of C8H18 is burned?

Homework Answers

Answer #1

Octane combustion reaction is:


   2C8H18 + 25O2 --> 16CO2 + 18H2O

In the reaction 2 moles C8H18 burns with O2 to produce 16 moles of CO2.

We have 24.1 g of C8H18, so we should calculate the no. moles we are burning.

No. moles of C8H18 = (mass of C8H18)/(mol. weight of C8H18) = 24.1 g/114.23 g/mol = 0.211 moles

Therefore, 2 moles C8H18 produces 16 moles of CO2

and we have 0.211 moles, so how many moles of CO2 produces =?

No. moles of CO2 produced = 0.211 moles x 16 moles/ 2 moles = 1.69 moles


Therefore, no. of moles of CO2 emitted into the atmosphere is = 1.69 moles

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