how many moles of solute particles are present in 1 ml of aqueous 0.006M Ba(OH)2
Barium hydroxide, Ba ( OH ) 2 , is completely ionized in aqueous solutions, it is a
STRONG base. The balanced equation showing this process would
be:
Ba ( OH ) 2 (s) ---> Ba 2+ (aq) + 2 OH 1-(aq)
Note that THREE ions are provided by each formula unit, so whatever
the concentration of
Ba ( OH ) 2 , the TOTAL concentration of ions will be THREE times
as great.
[ Ba ( OH ) 2 ] = 0.006M M so [ ions ] = 0.018 M
number of moles = (Molarity) X ( volume of solution in
litre)
number of moles ions = ( 0.018 M in ions ) x ( 0.001 L ) =
0.000018
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