Question

Oxidation NADH and FADH2 are often considered “energy currency” in cellular metabolism because they are generated directly from Glycolysis and the TCA cycle. Using the following half-cell potentials, calculate the Gibbs Free Energy that can be derived from the oxidation of NADH and FADH2. Use the Faraday Constant at 96,500 J/V mol.(should get two values)

FAD + 2H+ +2 e- = FADH2 Eo = -0.219V

NAD+ + H+ + 2 e- = NADH Eo = -0.320V

Answer 1

FAD + 2H+ +2 e- = FADH2 Eo = -0.219V

NAD+ + H+ + 2 e- = NADH Eo = -0.320V

NADH --------> NAD⁺ + H⁺ + 2e^-   E0 = 0.326v

FAD + 2H⁺ + 2e^- -------> FADH2 E0   = -0.219v

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                                                    E0cell = 0.11v

   n = 2

G   = -nEocell *F

             = -2*0.11*96500   = -21230J

G<0 it is spontanous reaction

           =