Which of the following transitions represent the emission of a photon with the largest energy?
A) n = 3 to n = 1
B) n = 2 to n = 5
C) n = 1 to n = 4
D) n = 6 to n = 3
E) n = 2 to n = 1
Ans: (D).
Reason: Emission is possible only when electron gets transformed
from higher orbit to the lower one that is from
outer to inner. And absorption is when electron gets switched from
inner to outer.
So 3 to 1, 6 to 3 and 2 to 1 transition leads to emission.
Larger the energy difference between orbits, then larger the
frequency and shorter the wavelength.
Energy difference will be more in 6 to 3, less in 3 to 1 and
still less in 2 to 1
So emission of highest frequency is possible for 6 to 3
transmission.
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