Calculate the cell potential for the voltaic cell based on the following half reactions at T = 25ºC:
Cr3+(aq) + 3e- → Cr(s) Eº = - 0.74 V
TiO2+(aq) + 2H+ (aq) + 1e- → Ti3+(aq) + H2O(l) Eº = + 0.10 V
Where, [Cr3+] = 1.0 x 10-4 M, [TiO2+] = 1.0 x 10-1 M, [H+] = 1.0 M, [Ti3+] = 5.0 x 10-2 M.
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