Question

You need to make a 100.00mL solution that is: 65mg/L sodium salicylate, 0.020 M FeCl3, and 0.050 M HCl. You will have available: solid FeCl3 6H20, iron(III)chloride hexahydrate, and solid sodium salicylate. How would you make this solution?

Answer 1

Preparation of 100 mL sodium salicylate solution: Weigh out exactly 6.5 mg of sodium salicylate and dissolve it with small quantity of solvent and makeup to 100 mL.

  Preparation of 100 mL FeCl₃ (0.020 M) solution:

                                                              

Therefore, Weight = 0.5406 g, this amount of FeCl3. 6H2O dissolve it in 100 mL standard flask with solvent to get 0.020 M solution.

  Preparation of 100 mL HCl (0.050 M) solution:

                                                                      11.6 M is the strength of the commercially available HCL solution.

Use the formulae M1V1=M2V2

Therefore, V1 = 0.4310 mL of concentrated HCl (commercial)

Pipette out exactly 0.4310 mL of concentrated HCl and makeup to 100 mL with solvent to get 0.050 M solution.