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NO2(g) + 7⁄2H2(g) ---> 2H2O(ℓ) + NH3(g) ΔH° = ??? kJ Using the following two equations:...

NO2(g) + 7⁄2H2(g) ---> 2H2O(ℓ) + NH3(g) ΔH° = ??? kJ

Using the following two equations:

2NH3(g) ---> N2(g) + 3H2(g) ΔH° = +92 kJ

1⁄2N2(g) + 2H2O(ℓ) ---> NO2(g) + 2H2(g)

 ΔH° = +170 kJ
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